How to store actual mysql data in an array in shell script

I am quite new in shell scripting and straight-away I am facing a problem. I want to query mysql database and store the result in an array in shell script. The query I am using is:

result=`mysql -e "select SequenceID from wsnapp.apptrafficnew where DateTime between '2012-12-27 11:40:00' AND '2012-12-27 12:30:00';"`

and I am also able store this data into an array by using:

array=( $( for i in $result ; do echo $i ; done ) );

but the problem is, it does not store the actual values. when I try to access the elements of array it shows something like that:

array[1]=SequenceID[1]

here I am only storing integers(1,2,3,4...) in my database so my actual value stored is 1 not the SequenceID[1].

I want to do some integer operations on the elements on array. So How do I store the actual values?

Please help.