How would you go about displaying records from one table missing out certain records if they are all on another table.
So I have a table which stores all members, and a table that store members who are down for each class. I wish to display all members minus the one from a certain class. Though some members are down for multiple classes, but I don't think that should affect it.
I've tried:
WHERE ((([Members].[ID])<>[Class 1 Members].[Member ID]));
It just runs and displays nothing.
Not sure missed something obvious, but shouldn't this just display the Members table minus the names which appear on the Session 1 Members table?
Also after this works I want to have a user input prompt so I can enter their Class Preferences, so each member when they applied had other classes they'd like as first and second preference. These are stored on another table. So would like it to list the members who are not in Class 1 but had it as a preference or any other class.
But tats just if its simply, don't wanna be too much trouble with what I think is probably simple stuff, but I'm very new to this.
So I have a table which stores all members, and a table that store members who are down for each class. I wish to display all members minus the one from a certain class. Though some members are down for multiple classes, but I don't think that should affect it.
I've tried:
WHERE ((([Members].[ID])<>[Class 1 Members].[Member ID]));
It just runs and displays nothing.
Not sure missed something obvious, but shouldn't this just display the Members table minus the names which appear on the Session 1 Members table?
Also after this works I want to have a user input prompt so I can enter their Class Preferences, so each member when they applied had other classes they'd like as first and second preference. These are stored on another table. So would like it to list the members who are not in Class 1 but had it as a preference or any other class.
But tats just if its simply, don't wanna be too much trouble with what I think is probably simple stuff, but I'm very new to this.