Hi,
This is how for I could get with LEFT OUTER JOIN, what's the proper way of doing this:
It produces:
Title1: About Us
Title1: Articles
-- Title2: Fruit
Title1: Articles
-- Title2: Meet
Title1: Articles
-- Title2: Vegetables
Title1: Donations
Title1: Services
Title1: Volunteers
Title1: News & Events
Title1: Home
Title1: Contact Us
'Articles' needs to be printed once as a parent of Fruit, Meet and Vegetables. And how do I mention in the query not to give empty values which I'm avoiding using if condition?
I will appreciate any sort of help in this matter.
This is how for I could get with LEFT OUTER JOIN, what's the proper way of doing this:
Code:
$sql = "
SELECT
menu1.title as title1,
menu2.title as title2
FROM menu_links AS menu1
LEFT OUTER JOIN menu_links AS menu2
ON menu1.menu_link_id = menu2.parent_link_id
WHERE menu1.parent_link_id = 0";
$stat = mysql_query($sql, $dblink);
while ($row = mysql_fetch_array($stat)) {
$list .= "Title1: ".$row["title1"]."<br>";
if ($row["title2"]) {
$list .= "-- Title2: ".$row["title2"]."<br>";
}
}Title1: About Us
Title1: Articles
-- Title2: Fruit
Title1: Articles
-- Title2: Meet
Title1: Articles
-- Title2: Vegetables
Title1: Donations
Title1: Services
Title1: Volunteers
Title1: News & Events
Title1: Home
Title1: Contact Us
'Articles' needs to be printed once as a parent of Fruit, Meet and Vegetables. And how do I mention in the query not to give empty values which I'm avoiding using if condition?
I will appreciate any sort of help in this matter.